Question #125845

how much heat must be added to a system at 298K for the number of accessible states to increase by a factor of 10^6?

Expert's answer

ΔQT=klnW2W1ΔQ=TklnW2W1=\frac{\Delta Q}{T}=k\ln{\frac{W_2}{W_1}}\to \Delta Q=T\cdot k\ln{\frac{W_2}{W_1}}=


=TklnW2W1=2981.381023ln106=5.681020J=T\cdot k\ln{\frac{W_2}{W_1}}=298\cdot1.38\cdot10^{-23}\cdot \ln{10^6}=5.68\cdot10^{-20}J




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