Question #125790
Carbon dioxide initially at 50 kPa, 400 K, undergoes a process in a closed system until its pressure and temperature are 2 MPa and 800 K, respectively. Assuming an ideal gas behaviour, find the entropy change of the carbon dioxide by assuming that the specific heats are constant. For the gas, take Cp = 0.846 kJ/kg.K and R = 0.1889 kJ/kg.K
1
Expert's answer
2020-07-10T10:25:43-0400

The entropy change of ideal gas is given by the following equation (https://www.grc.nasa.gov/WWW/K-12/airplane/entropy.html):


ΔS=CplnT2T1RlnP2P1\Delta S = C_p \ln\dfrac{T_2}{T_1} - R\ln\dfrac{P_2}{P_1}

where T1=400K,P1=50×103PaT_1 = 400K, P_1 = 50\times 10^3Pa are its parameters at the begining of the process and T2=800K,P1=2×106PaT_2 = 800K, P_1 = 2\times 10^6Pa are parameters at the end of the process. Thus, obtain:


ΔS=0.846103ln8004000.1889103ln210650103=110.4J/kgK\Delta S = 0.846\cdot 10^3 \ln\dfrac{800}{400} - 0.1889\cdot 10^{3}\ln\dfrac{2\cdot 10^6}{50\cdot 10^{3}} = \\ \approx 110.4 J/kg\cdot K

Answer. 110.4 J/kg.K.


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