Question #124364
One end of a uniform well lagged metal bar of length 0.8m and crossectional area of 4.0×10^-3m^2 is kept in steam at 100°c while the other end is melting in a well lagged container.The ice melt at a steady rate 5.5×10^-4KGS^-1 and the thermal conductivity of material of the bar is 401Am^-1k^-1.calculate the specific latent heat of fusion of ice
1
Expert's answer
2020-06-29T14:04:29-0400

Solution.

l=0.8m;l=0.8m;

A=4.0103m2;A=4.0\sdot10^{-3}m^2;

ΔT=100oC=100K;\Delta T=100^oC=100K;

mt=5.5104kgs1;\dfrac{m}{t}=5.5\sdot10^{-4}kgs^{-1};

K=401Js1m1K1;K=401Js^{-1}m^{-1}K^{-1};

Lf?;L_f-?;

ΔQΔt=(mt)Lf;\dfrac{\Delta Q}{\Delta t}=(\dfrac{m}{t})L_f;


ΔQΔt=ΔTlKA\dfrac{\Delta Q}{\Delta t}=\dfrac{\Delta T}{l}\sdot K\sdot A ;


ΔQΔt=100K0.8m401Js1m1K14.0103m2=200.5Js1;\dfrac{\Delta Q}{\Delta t}=\dfrac{100K}{0.8m}\sdot401Js^{-1}m^{-1}K^{-1}\sdot4.0\sdot10^{-3}m^2=200.5Js^{-1};


Lf=ΔQΔtmtL_f=\dfrac{\dfrac{\Delta Q}{\Delta t}}{\dfrac{m}{t}} ;

Lf=200.5Js15.5104kgs1=3.65105Jkg1;L_f=\dfrac{200.5Js^{-1}}{5.5\sdot10^{-4}kgs^{-1}}=3.65\sdot10^5Jkg^{-1};


Answer: Lf=3.65105Jkg1.L_f=3.65\sdot10^{5}Jkg^{-1}.



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