Solution.
"l=0.8m;"
"A=4.0\\sdot10^{-3}m^2;"
"\\Delta T=100^oC=100K;"
"\\dfrac{m}{t}=5.5\\sdot10^{-4}kgs^{-1};"
"K=401Js^{-1}m^{-1}K^{-1};"
"L_f-?;"
"\\dfrac{\\Delta Q}{\\Delta t}=(\\dfrac{m}{t})L_f;"
"\\dfrac{\\Delta Q}{\\Delta t}=\\dfrac{\\Delta T}{l}\\sdot K\\sdot A" ;
"\\dfrac{\\Delta Q}{\\Delta t}=\\dfrac{100K}{0.8m}\\sdot401Js^{-1}m^{-1}K^{-1}\\sdot4.0\\sdot10^{-3}m^2=200.5Js^{-1};"
"L_f=\\dfrac{\\dfrac{\\Delta Q}{\\Delta t}}{\\dfrac{m}{t}}" ;
"L_f=\\dfrac{200.5Js^{-1}}{5.5\\sdot10^{-4}kgs^{-1}}=3.65\\sdot10^5Jkg^{-1};"
Answer: "L_f=3.65\\sdot10^{5}Jkg^{-1}."
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