As per the given question,
m=1 kg
Pressure is constant.
Change in internal energy of the gas =-30kJ
Work one during the process=?
CP=840j/kg°c
CV=600j/kg°c
We know that ΔU=mCv(T1−T2)
Now substituting the values,
⇒−30000J=1×600(T1−T2)
⇒(T1−T2)=50∘C
The supplied heat or rejected heat,
⇒Q=mcp(T2−T1)
=840×−50
=−42kJ
We know that,
Q=ΔU+W
⇒W=Q−ΔU
⇒W=−42kJ+30=−12kJ
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