Question #122507
A closed system consisting of 1kg gaseous co² undergoes a reversible process at constant pressure causing a decrease of 30kj in internal energy
Determine the work done during the process
Take CP=840j/kg°c and CV=600j/kg°c
1
Expert's answer
2020-06-16T09:27:49-0400

As per the given question,

m=1 kg

Pressure is constant.

Change in internal energy of the gas =-30kJ

Work one during the process=?

CP=840j/kg°c

CV=600j/kg°c

We know that ΔU=mCv(T1T2)\Delta U= mC_v(T_1 -T_2)

Now substituting the values,

30000J=1×600(T1T2)\Rightarrow -30000J=1\times 600(T_1 -T_2)

(T1T2)=50C\Rightarrow (T_1 -T_2)= 50^\circ C

The supplied heat or rejected heat,

Q=mcp(T2T1)\Rightarrow Q=m c_p(T_2-T_1)

=840×50=840\times -50

=42kJ=-42kJ

We know that,

Q=ΔU+WQ=\Delta U+W

W=QΔU\Rightarrow W=Q-\Delta U

W=42kJ+30=12kJ\Rightarrow W=-42kJ+30=-12kJ


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