Question

If the activation energy for oxidation is 100 KJ mole^-1 , the ratio of oxidation rates at
800 degree Celcius and 500 degree Celcius is ?

Answer 1

Solution.

$E_a=100KJ/mol;$

$T_1=1073K;$

$T_2=773K;$

$k=e^{-\dfrac{E_a}{Rt}};$

$\dfrac{k_1}{k_2}=e^{-\dfrac{E_a}{R}(\dfrac{1}{T_1}-\dfrac{1}{T_2});}$ ;

$\dfrac{k_1}{k_2}=e^{4.35}=75.24;$

Answer: $\dfrac{k_1}{k_2}=75.24.$