Question #121611
A certain perfect gas is heated at constant pressure from 15 degrees celcius to 95 degrees celcius, the energy required is 1136 KJ / kg.
When this same gas is heated at constant volume to the same temperatures, the energy required is 808
KJ / kg.
Calculate:
(i) Mass heat at constant pressure, cp
(ii) Mass heat at constant volume, CV
(iii) The value of γ
(iv) The particular gas constant, Rp
(v) Molar mass, Mr
1
Expert's answer
2020-06-11T10:34:50-0400

Solution.

T1=15oC;T_1=15^oC;

T2=95oC;T_2=95^oC;

ΔQ1=1136KJ/kg;\Delta Q_1=1136KJ/kg;

ΔQ2=808KJ/kg;\Delta Q_2=808KJ/kg;

ΔQ1=cpΔT    cp=ΔQ1ΔT;\Delta Q_1=c_p\Delta T\implies c_p=\dfrac{\Delta Q_1}{\Delta T};

i)cp=1136KJ/kg80oC=14.2KJ/(kgoC);c_p=\dfrac{1136KJ/kg}{80^oC}=14.2KJ/(kg^oC);

ΔQ2=cvΔT    cv=ΔQ2ΔT;\Delta Q_2=c_v\Delta T\implies c_v=\dfrac{\Delta Q_2}{\Delta T};

ii)cv=808KJ/kg80oC=10.1KJ/(kgoC);c_v=\dfrac{808KJ/kg}{80^oC}=10.1KJ/(kg^oC);

iii)γ=cpcv;\gamma=\dfrac{c_p}{c_v};

γ=14.210.1=1.4;\gamma=\dfrac{14.2}{10.1}=1.4;

vi)Rm=cpcv;R_m=c_p-c_v;

Rm=14.210.1=4.1KJ/(kgoC)R_m=14.2-10.1=4.1KJ/(kg^oC) ;

v)R=RmM    M=RRm;R=R_mM\implies M=\dfrac{R}{R_m};

M=8.314100=0.002kg/mol;M=\dfrac{8.31}{4100}=0.002kg/mol;

The gas is hydrogen (H2).

Answer: i)cp=14.2KJ/(kgoC);c_p=14.2KJ/(kg^oC);

ii)cv=10.1KJ/(kgoC);c_v=10.1KJ/(kg^oC);

iii)γ=1.4;\gamma =1.4;

iv)Rm=4.1KJ/(kgoC);R_m=4.1KJ/(kg^oC);

v)M=0.002kg/mol.M=0.002kg/mol.




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