Question

A person runs 800m at an average speed of 6.0m/s and then the next 800 M at an average speed of 8.0 m/s. What is the total time required?

Answer 1

The total time required is the sum of distances divided by the corresponding speed:

$$t=\frac{d_1}{s_1}+\frac{d_2}{s_2}=\frac{800}{6}+\frac{800}{8}=233\text{ s},$$

or 3 min 53 s.