Let, Temperature in Fahrenheit scale is T,thus in centigrade scale temperature would be 3T.
We know that
"\\frac{C}{5}=\\frac{F-32}{9}"where , C is temperature in centigrade scale and F is in Fahrenheit scale.
Thus, from above formula we get,
"\\frac{3T}{5}=\\frac{T-32}{9}\\implies 27T=5T-160\\\\\n\\implies 22T=-160\\implies T=-7.27^{\\circ}F"
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