Question #120354
under a pressure of 14nm-2, some air has a volume of 1.5m3. determine its volume when its pressure is 10nm-2. assuming the temperature is kept constant
1
Expert's answer
2020-06-05T11:53:05-0400

Given data

Initial pressure is P1=14N/m2P_1=14 N/m^2

Final pressure is P2=10N/m2P_2=10 N/m^2

Initial volume is V1=1.5m3V_1=1.5 m^3

According to Boyle's law,

P1V1=P2V2P_1V_1=P_2V_2

The final volume is

V2=P1V1P2=(14N/m2)(1.5m3)10N/m2=2.1m3V_2=\frac{P_1V_1}{P_2}=\frac{(14 N/m^2)(1.5 m^3)}{10 N/m^2}=2.1 m^3


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Comments

Emmanuella
11.06.20, 18:43

Very correct, tested and trusted.

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