Heat is given out Q=m×Cp×ΔtQ = m\times C_{p}\times \Delta tQ=m×Cp×Δt
Q=0.05×2.3×10−3×(1000−280)=82800kJQ = 0.05 \times 2.3\times10^{-3}\times (1000-280) =82800 kJQ=0.05×2.3×10−3×(1000−280)=82800kJ
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