Given data are
V1=200cm3=2×10−4m3T1=150∘C=(150+273)=423KV2=150cm3=1.5×10−4m3 Let T2 is the temperature of hydrogen gas when volume of gas is V2=150cm3 .
From, The Charles's Law of constant pressure we get
T1V1=T2V2⟹T2=V1V2T1
Thus, On plugin the given data we get,
T2=2×10−4m31.5×10−4m3×423⟹T2=317.25K
Comments
The answer is very wrong, the correct answer is 216k.