Given data are
"V_1=200cm^3=2\\times 10^{-4}m^3\\\\T_1=150^{\\circ}C=(150+273)=423K\\\\\nV_2=150cm^3=1.5\\times 10^{-4}m^3"Let "T_2" is the temperature of hydrogen gas when volume of gas is "V_2=150cm^3" .
From, The Charles's Law of constant pressure we get
"\\frac{V_1}{T_1}=\\frac{V_2}{T_2}\\\\\n\\implies T_2=\\frac{V_2 T_1}{V_1}"
Thus, On plugin the given data we get,
"T_2=\\frac{1.5\\times 10^{-4}m^3}{2\\times 10^{-4}m^3}\\times 423\\\\\n\\implies T_2=317.25K"
Comments
The answer is very wrong, the correct answer is 216k.
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