Given, "L_0=20m" ,"T_i=100C,T_f=500C",thus "\\Delta T=T_f-T_i=400K".
"\\Delta L=L-L_0,\\& \\alpha_L=1.2 \\times 10^{-5}K^{-1}" ,
We know that
"L=L_0(1+ \\alpha \\Delta T)"Thus,
"L=20(1+1.2\\times 10^{-5}\\times 400)\\\\\n\\implies L =20.096m"Therefore, expansion of length is "\\Delta L=0.096m"
Comments
Leave a comment