Solution.
V1=5.000cm3;V_1=5.000cm^3;V1=5.000cm3;
T1=200oC;T_1=200^oC;T1=200oC;
V2=5.014cm3;V_2=5.014cm^3;V2=5.014cm3;
T2=1000oC;T_2=1000^oC;T2=1000oC;
αV−?;\alpha_V-?;αV−?;
αV=1V⋅ΔVΔT;\alpha_V=\dfrac{1}{V}\sdot\dfrac{\Delta V}{\Delta T};αV=V1⋅ΔTΔV;
αV=15.000cm2⋅0.014cm2800oC=3.5⋅10−61/oC;\alpha_V=\dfrac{1}{5.000cm^2}\sdot\dfrac{0.014cm^2}{800^oC}=3.5\sdot10^{-6}1/^oC;αV=5.000cm21⋅800oC0.014cm2=3.5⋅10−61/oC;
Answer: αV=3.5⋅10−6\alpha_V=3.5\sdot10^{-6}αV=3.5⋅10−6 oC-1.
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