Answer to Question #119295 in Molecular Physics | Thermodynamics for Adan

Question

A 0.350 m gold bar at 20.0 C heats up to 500.0 C. What is the change in length of the gold bar?

Answer 1

d₂₀ = 19.32 g/cm³

d₅₀₀ = 19.28 g/cm³

Δl = 0.35 × (19.32-19.28) = 0.014 m = 1.4 cm

Answer: Δl = 1.4 cm.