Solution.
"m=5g=5\\sdot10^{-3}kg;"
"t_1=0^oC;"
"t_2=50^oC;"
"\\lambda=332\\sdot10^3J\/kg;"
"\u0441=4200J\/kg^oC;"
Heat is needed to melt the ice:
"Q_1=\\lambda m;"
"Q_1=332\\sdot10^3J\/kg\\sdot5\\sdot10^{-3}kg=1660J;"
Heat is needed to heat ice water:
"Q_2=cm\\Delta t;"
"Q_2=4200J\/(kg^oC)\\sdot5\\sdot10^{-3}kg\\sdot50^oC=1050J;"
The whole amount of heat:
"Q=Q_2+Q_2;"
"Q=1660J+1050J=2710J;"
Answer: "Q=2710J."
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