Question

Heat flows through a wooden board 30 mm thick at 0.0086 W/cm³ ,when one of its sides is 20˚C warmer than the other. Determine the thermal conductivity of the wood.

Answer 1

Thermal conductivity

$K = \frac {Q} {A\times\Delta T}$

$K = \frac {0.0086} {3\times1\times(20+273)}$

$K = 9.78 \times 10 ^{-6} \frac {W} {cm^{2}\times K}$

$K = 0.0978 \frac {W} {m^{2}\times K}$