Solution:
A=2.2MJ;A=2.2 MJ;A=2.2MJ;
η=0.11;\eta=0.11;η=0.11;
Q−?;Q-?;Q−?;
The efficiency is calculated by the formula:
η=AQ; ⟹ Q=Aη;\eta=\dfrac{A}{Q};\implies Q=\dfrac{A}{\eta};η=QA;⟹Q=ηA;
Q=2.2MJ0.11=20MJ;Q=\dfrac{2.2MJ}{0.11}=20MJ;Q=0.112.2MJ=20MJ;
Answer: Q=20MJ.Q=20MJ.Q=20MJ.
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