Question #115630

A particle vector is given by r=2ti+t^2j. Find: (a) r at t=1 and t=3, respectively;

(b) the displacement of particle from t=1 to t= 3.

(c) the path equation of the particle

Expert's answer

r=r(t)=2ti+t2j=(2t,t2)\vec r=\vec r(t)=2t\vec i+t^2 \vec j=(2t,t^2)


(a) r(1)=(2,1),r(3)=(6,9)\vec r(1)=(2,1),\,\, \vec r(3)=(6,9)


(b) Δr=r(3)r(1)=(4,8)\Delta \vec r=\vec r(3)-\vec r(1)=(4,8)


(c) x=2t,y=t2y=0.25x2x=2t,\, y=t^2 \rightsquigarrow y=0.25x^2 is the path equation


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