r⃗=r⃗(t)=2ti⃗+t2j⃗=(2t,t2)\vec r=\vec r(t)=2t\vec i+t^2 \vec j=(2t,t^2)r=r(t)=2ti+t2j=(2t,t2)
(a) r⃗(1)=(2,1), r⃗(3)=(6,9)\vec r(1)=(2,1),\,\, \vec r(3)=(6,9)r(1)=(2,1),r(3)=(6,9)
(b) Δr⃗=r⃗(3)−r⃗(1)=(4,8)\Delta \vec r=\vec r(3)-\vec r(1)=(4,8)Δr=r(3)−r(1)=(4,8)
(c) x=2t, y=t2⇝y=0.25x2x=2t,\, y=t^2 \rightsquigarrow y=0.25x^2x=2t,y=t2⇝y=0.25x2 is the path equation
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