Answer to Question #114638 in Molecular Physics | Thermodynamics for Erica Alali

Question

The atmospheric pressure due to water is 1.3 x 106 Nm-2. What is the total pressure at the bottom of the ocean 10m deep. (Density of water = 1000kgm-3, g=10ms-2).

Answer 1

Solution.

$p_a=1.3\sdot10^6N/m^2;$

$h=10m;$

$\rho=1000kg/m^3;$

$g=10m/s^2;$

The total pressure on the ocean floor is equal to the sum of atmospheric pressure and hydrostatic pressure.

$p=p_a+p_h;$

Hydrostatic pressure is sought by the formula:

$p_h=\rho gh;$

$p_h=1000kg/m^3\sdot10m/s^2\sdot10m=10^5N/m^2;$

$p=1.3\sdot10^6N/m^2+10^5N/m^2=1.4\sdot10^6N/m^2;$

Answer: $p=1.4\sdot10^6N/m^2.$