Question

A fixed mass of gas of volume 600 cm3 at a temperature of 27° c is cooled at constant pressure to a temperature of 0° c. What is the change in volume

Answer 1

$\frac{V}{T}=const$

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$,

were $V_1$ and $V_2$ - initial and final volume of the gas, respectively; $T_1$ and $T_2$ - initial and final temperature of the gas, respectively.

$V_2=\frac{V_1 \cdot T_2}{T_1}$

$T [K] \approx T[ \degree C] +273$

$T_2 = 27 +273 = 300 \; K$

$T_1 = 0 +273 = 273 \; K$

$V_2=\frac{600 \cdot 273}{300} = 546 \; cm^3$

$\Delta V=V_2-V_1$

$\Delta V=546-600=-54 \; cm^3$

Answer: volume of the gas decrease by 54 cm³.