Question #107851

How much heat is required to heat a 540g of iron from 300c to 65°c?

Expert's answer

The amount of heat needed to heat of iron sample

Q=cmΔTQ=cm\Delta T=0.450Jg°C×540g×(6530)°C=8505J=0.450 \frac{\rm J}{\rm g\degree C}\times 540\:\rm g\times (65-30)\degree C=8505 \: J

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