Question #106815
What are classical limits? Explain how quantum distribution laws are reduced to classical Maxwell-Boltzmann distribution?
1
Expert's answer
2020-03-30T07:58:23-0400

Classical Limits:-The classical limit is the ability of a physical theory to approximate or "recover" classical mechanics when considered over special values of its parameters. The classical limit is used with physical theories that predict non-classical behavior.

The function f(e) depends on whether or not the particles obey the Pauli exclusion principle.

We know that for the bosons distribution function fBE(ϵ)=1eα+ϵkT1f_{BE}(\epsilon)=\dfrac{1}{e^{\alpha+\frac{\epsilon}{kT}}-1}

For fermions, the distribution function is fFE(ϵ)=1eα+ϵkT+1f_{FE}(\epsilon)=\dfrac{1}{e^{\alpha+\frac{\epsilon}{kT}}+1}


We know that max well distribution function f(ϵ)=AeϵkTf(\epsilon)=Ae^{\frac{-\epsilon}{kT}}


The number of particles having energy ϵ\epsilon at temperature T,

n(ϵ)=Ag(ϵ)eϵ/kTn(\epsilon)= Ag(\epsilon)e^{-\epsilon/kT}

So, for atom in ground state,

n(ϵ1)=Ag(ϵ1)eϵ1/kTn(\epsilon_1)= Ag(\epsilon_1)e^{-\epsilon_1/kT} --------(i)

So, for atom in first excited state,

n(ϵ2)=Ag(ϵ2)eϵ21/kTn(\epsilon_2)= Ag(\epsilon_2)e^{-\epsilon_21/kT} -----(ii)

Now dividing equation (ii) by (i)

n(ϵ2)n(ϵ1)=g(ϵ2)g(ϵ1)eϵ2ϵ1kT\dfrac{n(\epsilon_2)}{n(\epsilon_1)}=\dfrac{g(\epsilon_2)}{g(\epsilon_1)}e^{-\frac{\epsilon_2-\epsilon_1}{kT}}

=Aeϵ/kTAe^{-\epsilon/kT}


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