Answer to Question #106210 in Molecular Physics | Thermodynamics for Mesha

Question

A 1.0kg sample of steam is cooled from 110 degree celsius to 40 degree celsius. How much energy must be withdrawn for this to occur?

Answer 1

$$Q=mL+mc_s(T-T_0)+mc_w(T_0-T_1)$$

$$Q=1(2260+2.1(110-100)+4.2(100-40))$$

$$Q=2533\ kJ$$