700psia≈4826360 Pa
600psia≈4136854 Pa
0.0174ft3/lb=0.001086246503444 m3/kg
0.8794ft3/lb=0.05489914799588 m3/kg
Flow work of fluid as it enters (or exits) the system
w=p⋅v,
where p - pressure, v - specific volume.
(a) w1=4826360⋅0.001086246503444≈5.24 kJ/kg=2.25 Btu/lb Answer
(b) w1=4136854⋅0.05489914799588≈226 kJ/kg=97.2 Btu/lb Answer
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