Answer to Question #105406 in Molecular Physics | Thermodynamics for Kule

Question

a steam turbine develops 200 horsepower while receiving 400 BTU from each pound of steam passing through the turbine. calculate the pounds of steam per hour required by the turbine to produce this power

Answer 1

1 Horsepower= 746 W

Energy developed by the steam turbine =$power\times time$

$=200\times746\times60\times60=537,120,000 J=537120kJ$

This energy is developed by the some mass of steam

Let us assume 'x' pound of steam constitute this energy

Energy developed by steam =$x\times400$ BTU

1 BTU=1055 J

Energy developed by steam(in joules) = $x\times 400\times1055$

Energy developed by the steam turbine=Energy developed by steam

$537120000=x\times400\times1055$

x$=1272.8$ pounds