Question #105397
If the above problems is carried out as indicated, but with the additional provision that the process is also performed at a constant temperature of 327.9 F, calculate the change of entropy for the steam during the process, Btu/b.°R.
1
Expert's answer
2020-03-19T11:29:22-0400

So, ΔQ=889.2\Delta Q=889.2 Btu/lbBtu/lb


The change of entropy (T=327.9F=787.5R=constT=327.9 F=787.5 R=const )


ΔS=δQT=889.2787.5=1.129\Delta S=\int{\frac{\delta Q}{T}}=\frac{889.2}{787.5}=1.129 Btulb°R\frac{Btu}{lb\cdot °R} Answer












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