Answer to Question #105319 in Molecular Physics | Thermodynamics for Kule

Question

half a pound of gas undergoes a reversible non flow process at with the pressure remaining constant at 50 psia while the volume increases from 4ft^3 to 8ft^3. find the work done, BTU/lb

Answer 1

As per the given question,

amount of gas$=0.5 pound=\dfrac{0.5}{2.20}kg$

Pressure=50 psia=344738Pascal

Initial volume =$4ft^3$

Final volume =$8ft^3$

we know that work done $=p_1v_1\ln(\dfrac{V2}{V1})$

$=\dfrac{0.5}{2.20}\times 344738\ln{\dfrac{8}{4}}=0.22\times344738\ln{2}$

$=52569.91J$