As per the given question,
amount of gas=0.5pound=0.52.20kg=0.5 pound=\dfrac{0.5}{2.20}kg=0.5pound=2.200.5kg
Pressure=50 psia=344738Pascal
Initial volume =4ft34ft^34ft3
Final volume =8ft38ft^38ft3
we know that work done =p1v1ln(V2V1)=p_1v_1\ln(\dfrac{V2}{V1})=p1v1ln(V1V2)
=0.52.20×344738ln84=0.22×344738ln2=\dfrac{0.5}{2.20}\times 344738\ln{\dfrac{8}{4}}=0.22\times344738\ln{2}=2.200.5×344738ln48=0.22×344738ln2
=52569.91J=52569.91J=52569.91J
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