Question #105319
half a pound of gas undergoes a reversible non flow process at with the pressure remaining constant at 50 psia while the volume increases from 4ft^3 to 8ft^3. find the work done, BTU/lb
1
Expert's answer
2020-03-17T10:02:31-0400

As per the given question,

amount of gas=0.5pound=0.52.20kg=0.5 pound=\dfrac{0.5}{2.20}kg

Pressure=50 psia=344738Pascal

Initial volume =4ft34ft^3

Final volume =8ft38ft^3

we know that work done =p1v1ln(V2V1)=p_1v_1\ln(\dfrac{V2}{V1})

=0.52.20×344738ln84=0.22×344738ln2=\dfrac{0.5}{2.20}\times 344738\ln{\dfrac{8}{4}}=0.22\times344738\ln{2}

=52569.91J=52569.91J


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