Answer to Question #105317 in Molecular Physics | Thermodynamics for Kule

Question

two kilograms of gas undergo a reversible non-flow process at 350 kPa while the volume increases from 0.4734 m^3. find the work done, kj/kg

Answer 1

Heating of Fluid in a cylinder at Constant pressure {Isobaric Process}. Then work which done

$$A=\frac{p\cdot \Delta V}{m}$$

Calculating

$$A=\frac{350\cdot 0.4734}{2}=82.845 (kJ/kg)$$