Answer to Question #105090 in Molecular Physics | Thermodynamics for Andres

Question

A jet slows uniformly from 153 km/h to 0 km/h over 42 m. What is the jet's accelertion?

Answer 1

As per the given question,

Initial velocity of the jet $(u)=153 km/hour=\dfrac{153\times1000}{3600}m/sec=42.5 m/sec$

Final velocity of the jet (v)=0

Distance covered (d)=42m

Let the acceleration of the jet is a,

We know that , $v^2=u^2-2ad$

$\Rightarrow 0=42.5^2-2a\times42$

$\Rightarrow a=\dfrac{42.5\times 42.5}{2\times 42}=21.5 m/sec^2$

$a=21.5m/sec^2$