Answer to Question #104235 in Molecular Physics | Thermodynamics for John Lawrence jacob

Question

a brass ring has a diameter of 20cm when placed in melting ice at 0°Celsius. what will it's diameter be if it is placed in a boiling water?

Answer 1

$$d=d_0(1+\alpha (T-T_0))$$

$$d=20(1+19\cdot 10^{-6} (100-0))=20.038\ cm$$