Question

The probability that Juan will win a game of chess whenever he plays is ¼. If he plays twice, what are the odds that he wins the 1st game and loses the 2nd game?

Answer 1

Probability of winning the first game: 1/4;

Probability of losing the second game: 1-1/4=3/4

Probability of winning the first and losing the second game:

$\frac{1}{4}\cdot\frac{3}{4}=\frac{3}{16}$