Answer to Question #103488 in Molecular Physics | Thermodynamics for TIJANI Abdulkarim

Question

An object of density 300kgm-3 and volume of 0.001m3 is immersed in a water of density 200kgm-3, take g to be equal to 9.8m/sec2.determine;
(a):the weight in air
(b):the weight inside the water
(c):the upward force exerted by the water
(d):relative density

Answer 1

Given:

$\rho=300\:\rm kg/m^3;$

$V=0.001\:\rm m^3;$

$\rho_W=200\:\rm kg/m^3.$

(a) The weight in air

$W_1=mg=g\rho V=9.8\times 300\times 0.001=2.94\:\rm N.$

(b) The weight inside the water

$W_2=mg-g\rho_WV=9.8\times 100\times 0.001=0.98\:\rm N.$

(c) The upward force exerted by the water

$F_B=g\rho_W V=9.8\times 200\times 0.001=1.96\:\rm N.$

(d) The relative density

$\rho/\rho_W=300/200=3/2=1.5$