Question

Calculate the depth in the ocean at which the
pressure is three times atmospheric pressure.
Atmospheric pressure is 1.013 × 105 Pa. The
acceleration of gravity is 9.81 m/s2 and the density of sea water is 1025 kg/m3.
Answer in units of m.
Don't round answer.

Answer 1

$$p_0+\rho gh=3p_0$$

$$\rho gh=2p_0$$

$$(1025)(9.81)h=2(1.013 \cdot10^5 )$$

$$h=20.15\ m$$