Answer to Question #102203 in Molecular Physics | Thermodynamics for Phoebe

Question

how many calories are required to convert 100 grams of ice to steam?

Answer 1

$Q_{ice}=100(80)=8000\ cal$

$Q_{water}=100(1)(100)=10000\ cal$

$Q_{steam}=100(540)=54000\ cal$

$Q=8000+10000+54000=72000\ cal$