Question

if the same amount of heat energy is added to a beaker containing 100ml of ethanol and a beaker containing 100ml of water, which liquid experiences the greater rise in temperature.

Answer 1

According to the First law of thermodynamics:

$$Q = c * m * \Delta T, \text{ were: } Q \text{ - heat energy, } m \text{ - mass (liquid), } c \text{ - heat capacity}$$ $$\Delta T = \frac{Q}{c * m}$$

The greater rise in temperature had a liquid with a smaller heat capacity or (and) smaller mass.

The smaller heat capacity and smaller mass have ethanol:

$$C(\text{ethanol}) = 2.46$$ $$C(\text{water}) = 4,183$$ $$M(100\text{ml ethanol}) = 0.08\ \text{Kg}$$ $$M(100\text{ml water}) = 0.1\ \text{Kg}$$

Ethanol experiences the greater rise in temperature.

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