Solution.
1.n=1.5
W=p2×V2−p1×V11−nW = \frac{p2 \times V2 - p1 \times V1}{1-n}W=1−np2×V2−p1×V1
p1×V1n=p2×V2np1 \times V1^n = p2 \times V2^np1×V1n=p2×V2n
p2=p1×(V1V2)n=1.06 barp2 = p1 \times (\frac{V1}{V2})^n = 1.06 \ barp2=p1×(V2V1)n=1.06 bar
W = 17.6 kJ
2.n=1.0
pV = const
W=p1×V1×ln(V2V1)W = p1 \times V1 \times ln(\frac{V2}{V1})W=p1×V1×ln(V1V2)
W = 20.79 kJ
3.n=0
If n=0, p = const and,
W=p×(V2−V1)W = p \times (V2-V1)W=p×(V2−V1)
W = 30 kJ
Answer:
1.W = 17.6 kJ
2.W = 20.79 kJ
3.W = 30 kJ
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thanks for the help, but if you could give a little written explanation, it would have been better
Comments
thanks for the help, but if you could give a little written explanation, it would have been better