Answer to Question #99566 in Mechanics | Relativity for Shamma

Question

The amount of energy needed to power a 0.10-kW bulb for one minute would be just sufficient to lift a 1.0-kg object through a vertical distance of

Answer 1

Let the electrical energy is equal to gravitation potential energy. Then

$$Pt=mgh$$

So, the corresponding vertical distance

$$h=\frac{Pt}{mg}=\frac{100\:\rm W\times 60\: s}{1\:\rm kg\times 9.8\:\rm m/s^2}=612\:\rm m$$