Question #99021
Find the energy of a mosquitoes weighing 0.01g are flying at a speed of 0.5m/s
1
Expert's answer
2019-11-20T09:42:07-0500

The kinetic energy of a mosquito


KE=mv22KE=\frac{mv^2}{2}

=0.01×103kg×(0.5m/s)22=0.00000125J=1.25μJ=\frac{0.01\times 10^{-3}\:\rm kg\times (0.5\:\rm m/s)^2}{2}=0.00000125\:\rm J=1.25\: \mu J


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

Assignment Expert
20.11.19, 17:03

Dear Kazeem Gbenga Isiaka, You're welcome. We are glad to be helpful. If you liked our service please press like-button beside answer field. Thank you!

Kazeem Gbenga Isiaka
20.11.19, 16:49

Thanks very much

LATEST TUTORIALS
APPROVED BY CLIENTS