Answer to Question #98976 in Mechanics | Relativity for Juan Mora

Question

The force required to stretch a Hooke's-Law spring varies from 0 N to 44.4 N as we stretch the spring by moving one end 18 cm from its unstressed position.
Find the force constant of the spring.
Answer in units of N/m.

Answer 1

The Hooke's law state

$$F=k\Delta x$$

Thus, the force constant of a spring

$$k=\frac{F}{\Delta x}=\frac{44.4\:\rm N}{0.18\:\rm m}=247\:\rm N/m$$