Question #9871

two balls of different masses are thrown vertically upward with same initial velocity .calculate the ratio of ratio of maximum height attained by them

Expert's answer

H=gt22H = \frac {g t ^ {2}}{2}v=gt,t=vg;\boldsymbol {v} = \boldsymbol {g} \boldsymbol {t}, \boldsymbol {t} = \frac {\boldsymbol {v}}{\boldsymbol {g}};H=gv222=v22gH = \frac {g \frac {v ^ {2}}{2}}{2} = \frac {v ^ {2}}{2 g}


As acceleration of free falling does not depend on weight, balls will rise on equal altitude:


H1=H2,ratio=H1H2=1H 1 = H 2, \quad \text{ratio} = \frac {H 1}{H 2} = 1


Answer:

Ratio = 1.

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