Question

A young boy swings a yo-yo horizontally above his head so that the yo-yo has a centripetal acceleration of 240 m/s[sup]2[/sup]. If the yo-yo’s string is 0.56 m long, what is the yo-yo’s tangential speed?

Answer 1

By the equations of the rotational motion:
a= ω² R ; v=ω*R
ω = √(a/R) = √(240/0.56) = 20.7
Thus the linear speed would be
v = 20.7* 0.56 = 11.6 m/s