A young boy swings a yo-yo horizontally above his head so that the yo-yo has a centripetal acceleration of 240 m/s[sup]2[/sup]. If the yo-yo’s string is 0.56 m long, what is the yo-yo’s tangential speed?
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Expert's answer
2010-11-13T02:07:00-0500
By the equations of the rotational motion: a= ω2 R ; v=ω*R ω = √(a/R) = √(240/0.56) = 20.7 Thus the linear speed would be v = 20.7* 0.56 = 11.6 m/s
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