Question #97639

A person's hand pushed down with a force of 40.0N on a 8.50kg book that is sitting on a table. what is the magnitude of the normal force on the book? what is the magnitude and direction (in words) of the force on the person's hand due to the book ?

Expert's answer

The magnitude of the normal force on the book:


N=F+mg=40+(8.5)(9.8)=123 NN=F+mg=40+(8.5)(9.8)=123\ N

The magnitude and direction of the force on the person's hand due to the book: 40.0 N upwards.


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