Question #97638
a 76.5N block is being held in place by static friction on a ramp that makes an angle of 35.7 degree with the horizontal. what is the magnitude of the normal force on the block ?
1
Expert's answer
2019-10-31T11:14:50-0400

The magnitude of the normal force on the block:


N=Wcos35.7°=76.5cos35.7°=62.1 NN=W\cos{35.7 \degree}=76.5\cos{35.7 \degree}=62.1\ N


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