Coefficient of friction =μ=\mu=μ
Frictional force between road and sledge =12μmg=\frac{1}{2}\mu mg=21μmg
∵ as the length increases from 0 to l force increases from 0 to μmg\because\ as \ the \ length\ increases \ from\ 0\ to \ l\ force\ increases\ from\ \\0\ to \ \mu mg∵ as the length increases from 0 to l force increases from 0 to μmg
Work done against friction as the sledge shift completely on the road=12μmgl=\frac{1}{2}\mu mgl=21μmgl
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments