(a) Rate of acceleration is same for complete flight = 10 m sec−2
(b)
We know that,R=gu2sin2θputting values,200=u2sinθcosθ .....(1)also,time of flight,T=g2usinθor130=usinθ .....(2)putting the (2) in (1),we get,ucosθ=130200 ......(3) Dividing (2) from (3)
we get,
tanθ=84.5orθ=89.322°Then,initial speed ,u=sin89.322°130=130.01 m sec−1
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