Question

An airplane is flying with a velocity of 240m/s at an angle of 30.0 degrees. with the horizontal. when the altitude of the plane is 2.4km, a flare is released from the plane. the flare hits the target on the ground. What’s the angle?

Answer 1

$$h=-v\sin{30}t+0.5gt^2$$

$$2400=240\sin{30}t-0.5(9.8)t^2$$

$$t=37.5\ s$$

$$u_x=v\cos{30}=240\cos{30}=207.8\frac{m}{s}$$

$$u_y=gt-v\sin{30}=(9.8)(37.5)-240\sin{30}=247.5\frac{m}{s}$$

The angle is

$$\theta=\arctan{\frac{247.5}{207.8}}=50.0\degree$$

below the horizontal.