Answer to Question #96620 in Mechanics | Relativity for Sam
2019-10-16T01:23:48-04:00
An airplane is flying with a velocity of 240m/s at an angle of 30.0 degrees. with the horizontal. when the altitude of the plane is 2.4km, a flare is released from the plane. the flare hits the target on the ground. What’s the angle?
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2019-10-17T11:11:29-0400
h = − v sin 30 t + 0.5 g t 2 h=-v\sin{30}t+0.5gt^2 h = − v sin 30 t + 0.5 g t 2
2400 = 240 sin 30 t − 0.5 ( 9.8 ) t 2 2400=240\sin{30}t-0.5(9.8)t^2 2400 = 240 sin 30 t − 0.5 ( 9.8 ) t 2
t = 37.5 s t=37.5\ s t = 37.5 s
u x = v cos 30 = 240 cos 30 = 207.8 m s u_x=v\cos{30}=240\cos{30}=207.8\frac{m}{s} u x = v cos 30 = 240 cos 30 = 207.8 s m
u y = g t − v sin 30 = ( 9.8 ) ( 37.5 ) − 240 sin 30 = 247.5 m s u_y=gt-v\sin{30}=(9.8)(37.5)-240\sin{30}=247.5\frac{m}{s} u y = g t − v sin 30 = ( 9.8 ) ( 37.5 ) − 240 sin 30 = 247.5 s m The angle is
θ = arctan 247.5 207.8 = 50.0 ° \theta=\arctan{\frac{247.5}{207.8}}=50.0\degree θ = arctan 207.8 247.5 = 50.0° below the horizontal.
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