Answer to Question #96551 in Mechanics | Relativity for yuvraj

Question

a ball thrown with velocity of 39.2m/s at a angle of 30` with the horizantal . calculat the maxium height and time flight

Answer 1

The time flight:

$t=\frac{2v\sin{30}}{g}$

$t=\frac{2(39.2)\sin{30}}{9.8}=4\ s$

The maxium height:

$h=\frac{(v\sin{30})^2}{2g}$

$h=\frac{(39.2\sin{30})^2}{2(9.8)}=19.6\ m$