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Question #96543
Two bodies A and B of equal masses moving with velocities (10km/s, 030°) and (15km/s, 090°) impinges and coalesced. Find the initial velocity with which the composite body begins to move immediately after the collision
Expert's answer
From the conservation of momentum:
m
v
1
+
m
v
2
=
2
m
v
m\bold{v_1}+m\bold{v_2}=2m\bold{v}
m
v
1
+
m
v
2
=
2
m
v
0.5
(
10
cos
30
,
10
sin
30
)
+
0.5
(
0
,
15
)
=
(
v
x
,
v
y
)
0.5(10\cos{30},10\sin{30})+0.5(0,15)=(v_x,v_y)
0.5
(
10
cos
30
,
10
sin
30
)
+
0.5
(
0
,
15
)
=
(
v
x
,
v
y
)
v
x
=
4.33
m
s
,
v
y
=
10
m
s
v_x=4.33\frac{m}{s}, v_y=10\frac{m}{s}
v
x
=
4.33
s
m
,
v
y
=
10
s
m
Thus,
v
=
4.3
3
2
+
1
0
2
=
10.9
m
s
v=\sqrt{4.33^2+10^2}=10.9\frac{m}{s}
v
=
4.3
3
2
+
1
0
2
=
10.9
s
m
θ
=
arctan
10
4.33
=
66.6
°
\theta=\arctan{\frac{10}{4.33}}=66.6\degree
θ
=
arctan
4.33
10
=
66.6°
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