Answer to Question #96530 in Mechanics | Relativity for suresh

Question

A body of mass 30 kg kept on a rough horizontal surface of coefficient of friction is 0.3 then frictional force between block and the surface is

Answer 1

For the equilibrium:

$$N=W=mg$$

The frictional force between block and the surface is

$$F_f=\mu N=\mu mg=(0.3)(30)(9.8)=88\ N$$