Answer to Question #96404 in Mechanics | Relativity for Jaydeep gohil

Question

An aeroplane moves horizantaly at 162km/h speed at height of 2km above the ground, towards a fixed Target on a ground. If a bomb is to released to hit the target from the aeroplane detarmine where should the bomb be released? Also calculate the velocity with which the bomb strike the target

Answer 1

To cover the vertical distance, $s=u\times t+\frac{1}{2}a\times t^2$

$s=2Km=2000m$

$2=\frac{1}{2}\times9.8\times t^2$

$t=20.20s$

So horizontal distance at which the bomb should be dropped$=v\times t=45\times20.20=909m$

Speed at which bomb is dropped$=9.8\times t=9.8\times20.20=197.96\frac{m}{sec}$